InterviewSolution
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InterviewSolution
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The line `(x-2)/3=(y+1)/2=(z-1)/1`intersects the curve `x y=c^(I2),z=0`if `c`is equal toa. `+-1`b. `+-1//3`c. `+-sqrt(5)`d. none of theseA. `ne1`B. `+-1//3`C. `+-sqrt5`D. none of these |
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Answer» Correct Answer - c We have z=0 for the point, where the line intersects the curve. Therefore, `(x-2)/(3)=(y+1)/(2)=(0-1)/(-1)` `implies(x-2)/(3)=1and(y+1)/(2)=1` `impliesx=5andy=1` Putting these valese in `xy=c^(2)` we get `5=c^(2)orc=+-sqrt5` |
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