The line `(x-4)/1=(y-2)/1=(z-k)/2` lies exactly on the plane `2x=4y+z=7` then the value of k is (A) 7 (B) -7 (C) 1 (D) none of theseA. `-7`B. 7C. 4D. `-4`

The line `(x-4)/1=(y-2)/1=(z-k)/2` lies exactly on the plane `2x=4y+z=

1.	The line `(x-4)/1=(y-2)/1=(z-k)/2` lies exactly on the plane `2x=4y+z=7` then the value of k is (A) 7 (B) -7 (C) 1 (D) none of theseA. `-7`B. 7C. 4D. `-4`
Answer» Correct Answer - b Clearly, the given line passes through the point (4,2,k). Since, the given line lies in the plane `2x-4y+z=7`, so the above point lies in this plane. `therefore (2xx4)-(4 xx 2)+k=7 rArr k=7`.

Find the equation of a line passing through the point `(2hati-3hatj-5hatk)` and perpendicular to the plane`vecr.(6hati-3hatj+5hatk) +2=0`. Also find the point of intersection of this line and the plane.
If the points `(1,1,p)` and `(-3,0,1)` be equidistant from the plane `vecr.(3hati+4hatj-12hatk)+13`, find the values of p.
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Find the length of the foot of the perpendicular from the point (1,1,2) to the plane `vecr.(2hati-2hatj+4hatk)+5=0`
Find the coordinates of the image of the point P`(1, 3, 4)` in the plane `2x-y+z+3=0`.
Find the equationof the plane passing through each group of points. i) A(2,2,-1), B(3,4,2) and C(7,0,6) ii) A(0,-1,-1), B(4,5,1) and C(3,9,4) iii) A(-2,6,-6), B(-3,10,-9) and C(-5,0,-6).
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Find the distance of the point `(-1,-5,-10)` from the point of the intersection of the line `vecr = 2hati-2hatk+lambda(3hati+4hatj+2hatk)` and the plane `vecr.(hati-hatj+hatk) = 5`.
Find the distance of the point `(2hati-hatj-4hatk)` from the plane `vecr.(3hati-4hatj+12hatk)=9`.