The line x+y=0 bisects two chords drawn from the point (1+k√22,1−k – InterviewSolution

1.	The line x+y=0 bisects two chords drawn from the point (1+k√22,1−k√22) to the circle x2+y2−(1+k√22)x−((1−k√2)2)y=0. Then the minimum integral value of \|k\| is
Answer» The line $x + y = 0$ bisects two chords drawn from the point $(\frac{1 + k \sqrt{2}}{2}, \frac{1 - k \sqrt{2}}{2})$ to the circle $x^{2} + y^{2} - (\frac{1 + k \sqrt{2}}{2}) x - (\frac{(1 - k \sqrt{2})}{2}) y = 0.$ Then the minimum integral value of $\| k \|$ is

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