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The line `x+y=6` is normal to the parabola `y^(2)=8x` at the point.A. (4,2)B. (2,4)C. (2,2)D. (3,3) |
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Answer» Correct Answer - B `y=-x+6` ..(1) is normal to `y^(2)=4ax` the of line (1) Now equation of any normal to the parabola `y^(2)=4ax` is `y=mx-2am-am^(3)` Comparing (1) and (2) we get `mx=-ximpliesm=-1` `6=-2am-am^(3)` `6=-2a(-1)-a(-1)^(3)` `6=2a+a=3aimpliesa=2` `because` point `(am^(2),-2am)=(2(-1)^(2),-2xx2xx-1)=(2,4)` |
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