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The line xa+yb=1 moves in such a way that 1a2+1b2=1c2 where c is a constant. The locus of foot of perpendicular from the origin on the given line will be |
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Answer» The line xa+yb=1 moves in such a way that 1a2+1b2=1c2 where c is a constant. The locus of foot of perpendicular from the origin on the given line will be |
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