1.

The line `y=m x-((a^2-b^2)m)/(sqrt(a^2+b^2m^2))`is normal to the ellise `(x^2)/(a^2)+(y^2)/(b^2)=1`for all values of `m`belonging to`(0,1)`(b) `(0,oo)`(c) `R`(d) none of theseA. (0,1)B. `(0,oo)`C. RD. none of these

Answer» The eqquation of the normal to the given ellipse at the point `P(a cos theta, b sin theta) "is" ax sec theta- "by cosec" theta=a^(2)-b^(2)`. Then,
`y=((a)/(b) tan theta)x-((a^(2)-b^(2)))/(b) sin theta" "(1)`
Let `(a)/(b) tan theta=m`
so that
`y=((a)/(b) tan theta)x-((a^(2)-b^(2)))/(b) sin theta" "(1)`
Hence, the equation of the normal equation (1) becomes
`y=mx-((a^(2)-b^(2)))/(sqrt(a^(2)+b^(2)m^(2)))` ltbrlt `:. m in R, "as" m=(a)/(b) tan theta in R`


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