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The lines represented by `x^(2)+2lambda xy+2y^(2)=0` and the lines represented by `1+lambda_x^(2)-8xy+y^(2)=0` are equally inclined, thenA. `lambda` is any real numberB. `lambda gt 2`C. `lambda = pm2`D. `lambda lt -2` |
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Answer» Correct Answer - C If the lines given by the two equations are equally inclined then they have the same bisectors. Therefore, equations `(x^(2)-y^(2))/(1-2)=(xy)/(lambda) and (x^(2)-y^(2))/(1+lambda-1)=(xy)/(-4)` represent the same pair of lines. `rArr" "lambdax^(2)+xy-lambday^(2)=0 and 4x^(2)+lambdaxy-4y^(2)=0`, represent the same pair of lines `therefore" "(lambda)/(4)=(1)/(lambda)=(-lambda)/(-4)rArr lambda^(2)=4 rArr lambda= pm 2` |
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