

InterviewSolution
Saved Bookmarks
1. |
the linkage map of X -chroosomes of fruitfly has 66 units with yellow body gene (y) at one end and bobbed hair (b) gene at the other end the recomnation frequency between these two genes (y and b) should be :A. 0.66B. `le50`C. `gt50`D. 1 |
Answer» Correct Answer - C The recombination fequency of y and b gene will be lt 50% |
|