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1. |
the linkage map of X -chroosomes of fruitfly has 66 units with yellow body gene (y) at one end and bobbed hair (b) gene at the other end the recomnation frequency between these two genes (y and b) should be :A. `le 50%`B. `100%`C. `66%`D. `gt 50%` |
Answer» Correct Answer - B The actual distance between two genes is said to be equivalent to the percentage of crossing over between these two genes. Since, the two genes lie at the ends of the chromosome, there are 100% chances of their segregation during crossing over. |
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