1.

The litres of CO_(2) represented by 4.4 g of CO_(2) at S.T.P are :

Answer»

2.4 litres
2.24 litres
44 litres
22.4 litres

Solution :44 G (MOLAR mass) of `CO_(2)` REPRESENT
= 22.4 L at S.T.P
4.4 of `CO_(2)` represent
`= ((22.4L))/((44g))xx(4.4g)=2.24L`.


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