InterviewSolution
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InterviewSolution
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The load current in the transmitting antenna of an unmodulated `AM` transmitter is `6 Amp`. What will be the antenna current when modulation is `60%`. |
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Answer» Total power carried by `AM` wave `P_(T)=P_(C)(1+(m^(2))/(2))`……(`1`) Where `P_(c)` is the power of carrier component and `m` is the modulation factor. If `R` is the resistance, `I_(m)` the antenna load current when modulation is `60%` and `I_(c)` is the antenna load current when unmodulated, then `(P_(T))/(P_(C))=(I_(m)^(2)R)/(I_(c)^(2)R)`, `:. 1+(m^(2))/(2)=(I_(m)^(2))/(I_(c)^(2))` using (`1`) or `I_(m)=I_(c)sqrt({(1+(m^(2))/(2))})` Given `I_(c)=6Amp`, `m=0.6` `I_(m)=6[1+((0.6)^(2))/(2)]=6[1.086]=6.52Amp` |
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