The locus of a point, which is equidistant from (2,6) and (2, 8) is __ – InterviewSolution

InterviewSolution

1.	The locus of a point, which is equidistant from (2,6) and (2, 8) is ______A. `y = 7`B. `x = 7`C. `x = 2`D. `y = 2`
Answer» Correct Answer - A Let A = (2,6) B = (2,8) The required locus is the perpendicular bisector of `overline(AB)` Let K be the point of intensection of `overline(AB)` and its perpendicular bisector. `K = ((2 + 2)/(2), (8 + 6)/(2)) = (2,7)` Slope of `overline(AB) = ((8 - 6)/(2 -2))`is not defined. `:. overline(AB)` is parallel to Y-axis. The required line is parallel to X-axis `:.` The required line is Y = 7 (From Eqs. (1) and (2)).

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