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The locus of mid-points of a focal chord of the ellipse `x^2/a^2+y^2/b^2=1` |
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Answer» Let the midpoint of the focal chord the given ellipse be (h,k) . Then its equation is `(hx)/(k)+(ky)/(b^(2))=(h^(2))/(a^(2))+(k^(2))/(b^(2))" " ["Using"T=S_(1)]` Since this passes thoughb (ae,0), we have or `(hae)/(a)=(h^(2))/(a^(2))+(k^(2))/(b^(2))` Therefore, the locus of (h,k) is `(ex)/(a)=(x^(2))/(a^(2))+(y^(2))/(b^(2))` |
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