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The longest wavelength doublet absorption transition is oberved at 58 and 589-6 nm. Calculate the frequency of each transition and the energy difference between the two excited states |
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Answer» SOLUTION :`lamda_(1) = 589 nm = 589 xx 10^(-9) m " " :. v_(1) = (C)/(lamda_(1)) = (3.0 xx 10^(8) ms^(-1))/(589 xx 10^(-9) m) = 5.093 xx 10^(14) s^(-1)` `lamda_(2) = 589.6 nm = 589.6 xx 10^(-9)m :. v_(2) = (c)/(lamda_(2)) = (3.0 xx 10^(8) ms^(-1))/(589.6 xx 10^(-9) m) = 5.088 xx 10^(14) s^(-1)` `DELTA E = E_(2) - E_(1) = h (v_(2) - v_(1)) = (6.626 xx 10^(-34) Js) (5.093 - 5.088) xx 10^(14) s^(-1) = 3.31 xx 10^(-22) J` |
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