1.

The longest wavelengthdouble absorptiontransitionis observedat 589and 589nmCalculate the frequencyof eachtransitionandenergydifferencebetweentwoexcitedstates.

Answer»

Solution :Firstlinewavelength
`lambda_(1)= 589nm = 589 xx 10^(9)m= 589 xx 10^(7) m`
frequency`v_(1) = (c )/(LAMBDA) = (3.0 xx 10^(8)MS^(_1))/(5.89 xx 10^(7) m)`
`=5.0934 xx 10^(14) s^(-1)`
Secondlinewavelength
`lambda_(2)= 589 NM = 589 .6 xx 10^(9) nm =5.896 xx 10^(7) m`
Differenceof doubletfrequency`(v_(1)-v_(2)) Delta v`
andenergydifference`Delta E= hDelta E`
`(6.626 xx 10^(34 ) js) ( 0.0052 xx 10^(14)s^(-1))`
`=0.03446 xx 10^(20)J = 3.446 xx 10^(22) J`


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