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The longest wavelengthdouble absorptiontransitionis observedat 589and 589nmCalculate the frequencyof eachtransitionandenergydifferencebetweentwoexcitedstates. |
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Answer» Solution :Firstlinewavelength `lambda_(1)= 589nm = 589 xx 10^(9)m= 589 xx 10^(7) m` frequency`v_(1) = (c )/(LAMBDA) = (3.0 xx 10^(8)MS^(_1))/(5.89 xx 10^(7) m)` `=5.0934 xx 10^(14) s^(-1)` Secondlinewavelength `lambda_(2)= 589 NM = 589 .6 xx 10^(9) nm =5.896 xx 10^(7) m` Differenceof doubletfrequency`(v_(1)-v_(2)) Delta v` andenergydifference`Delta E= hDelta E` `(6.626 xx 10^(34 ) js) ( 0.0052 xx 10^(14)s^(-1))` `=0.03446 xx 10^(20)J = 3.446 xx 10^(22) J` |
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