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The loss of weight of a solid when immersed in a liquid at 0^(0) C is W_(0) . If alpha and beta are the volume coefficients of expansion of the solid and the liquid respectively, then the loss of weight at t^(0C is approximately |
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Answer» SOLUTION :Loss of wt at `0^(0) C = V_(0) rho_(0) g = w_(0)` `V_(0)` = volume of body at `0^(0) `C `V_(1) ` = volume of body at `t_(1)^(0) ` C loss of weigth at `t_(1)^(0) C = V_(1) rho_(1) g = w_(1)` `(w_(1))/(w_(0)) = (V_(1)rho_(1))/(V_(0)rho_(0)) = (d_(0) )/(d_(1)) xx (rho_(1))/(rho_(0))` where `d_(0)` is DENSITY of solid at `0^(0)` C and `rho_(0)` is density of LIQUID at `0^(0)` C. `(w_(1))/(w_(0)) = (d_(0) (1 + alpha t))/(d_(0))(rho_(0))/((1 + beta t)rho_(0)) = (1 + alphat t)/(1 + beta t)` `w_(1) = w_(0) (1 + alpha t ) (1 - beta t ) = w_(0) [ 1 + (alpha - beta ) t] ` |
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