1.

The lower end of a capillary tube of radius r is placed vertically in water. Then with the rise of water in the capillary, heat evolved is :

Answer»

`+(pi^(2)r^(2)H^(2))/(j)dg`
`+(PIR^(2)h^(2))/(2J)dg`
`-(pir^(2)h^(2))/(2j)dg`
`-(pir^(2)h^(2))/(j)dg`

ANSWER :B


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