1.

The M.I. of a wheel of mass 8 kg and radius of gyration 25 cm isA. `5 kg m^(2)`B. `1.5 kg m^(2)`C. `2.5 kg m^(2)`D. `0.5 kg m^(2)`

Answer» Correct Answer - D
`I = mK^(2) = 8xx(0.25)^(2)= 8xx((1)/(4))^(2)`
`= 8xx(1)/(16)=(1)/(2)=0.5 kg m^(2)`
`I = 0.5 kg m^(2)`


Discussion

No Comment Found

Related InterviewSolutions