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The M.I. of a wheel of mass 8 kg and radius of gyration 25 cm isA. `5 kg m^(2)`B. `1.5 kg m^(2)`C. `2.5 kg m^(2)`D. `0.5 kg m^(2)` |
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Answer» Correct Answer - D `I = mK^(2) = 8xx(0.25)^(2)= 8xx((1)/(4))^(2)` `= 8xx(1)/(16)=(1)/(2)=0.5 kg m^(2)` `I = 0.5 kg m^(2)` |
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