The magnetic field along the axis of a circular coil is found to beB =

1.	The magnetic field along the axis of a circular coil is found to beB = \(\frac{\mu_0Ia^2}{2(r^2+a^2)^{3/2}}\)1. What is the magnetic field along the axis if r>>a 2.Compare the above magnetic field with the electric field along the axis of an electric dipoleWhat is the equation of magnetic dipole moment?
Answer» 1. B = \(\frac{\mu_0/a^2}{2r^3}\) 2. Electric field due to electric dipole, E = \(\frac{1}{4\pi ε_0}\frac{P}{r^3}\) magnetic field due to magnetic dipole B = \(\frac{\mu_0}{4\pi}\frac{m}{x^3}\) Magnetic moment m = IA

The magnetic field along the axis of a circular coil is found to beB = \(\frac{\mu_0Ia^2}{2(r^2+a^2)^{3/2}}\)1. What is the magnetic field along the axis if r>>a 2.Compare the above magnetic field with the electric field along the axis of an electric dipoleWhat is the equation of magnetic dipole moment?

Answer»

1. B = \(\frac{\mu_0/a^2}{2r^3}\)

E = \(\frac{1}{4\pi ε_0}\frac{P}{r^3}\) magnetic field due to magnetic dipole

B = \(\frac{\mu_0}{4\pi}\frac{m}{x^3}\)