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The magnetic field at the centre of a current carrying circular loop of radius R, is B1. The magnetic field at a point on its axis at a distance R from the center of the loop is B2. Then the ratio (B1/B2) is :(a) 2√2(b) 1/√2(c) √2(d) 2 |
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Answer» Option : (a) 2√2 |
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