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The magnetic field at the centre of the circular loop as shown in Fig. when a single wire is bent to form a circular loop and also extends to form straight sections is A. `(mu_(0)I)/(2R)otimes`B. `(mu_(0)I)/(2R)(1+(1)/(pisqrt(2)))odot`C. `(mu_(0)I)/(2R)(1-(1)/(pisqrt(2)))odot`D. `(mu_(0)I)/(2R)(1+(1)/(pisqrt(2)))otimes` |
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Answer» `B_(AB)=(mu_(0)I)/(4piR)[sin90^(@)+sin(-45^(@))]ox` `B_(BC)=(mu_(0)I)/(4piR)[sin90^(@)+sin45^(@)]o.` `B_(0)=B_(AB)+B_(BC)+B_("circular")` |
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