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The magnetic field in a plane electromangnetic wave is given by `B=(300muT) sin (5.0xx10^-5x^-1)(t-x//c)` Find(i) the maximum electric field and (ii) The average energy density corresponding to the electric field. |
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Answer» Correct Answer - `9xx10^4Vm^-1 ; 1.79xx10^-2Jm^-3` Here, `B_0=300muT=3000xx10^-6T` `=3xx10^-4T` `E_0=cB_0 =(3xx10^8)xx(3xx10^-4)` `=9xx10^4Vm^-1` `u_E=1/4in_0E_0^2=1/4xx(8.85xx10^-12)xx(9xx10^4)^2` `=1.79xx10^-2Jm^-3` |
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