1.

The magnetic field in a plane em wave is given by : By = 12× 10−8 sin (1.20× 107Z + 3.60 × 1015t) Tesla. Calculate the : (i) energy density associated with the em wave (ii) speed of the wave

Answer»

(i) Here, 

B0 =12× 10−8 Tesla 

E0 = cB0 

= 3× 10−8 × 12 × 10−8

= 36 V/m 

Average energy density of electric field,

uE \(\frac{1}{4}\)0\(E^2_0\)

\(\frac{1}{4}\) \(\times\) 8.85 × 10−12 × 36 × 36

= 2867.4 × 10−12 

= 2.87× 10−9 J/m

Average energy density of magnetic field, 

uB = uE

∴ Energy density associated with the em wave.

u = uE+ uB 

= 2uE 

= 2× 2.87 × 10−9 

= 5.74 × 10−9 J/m3

(ii) \(\frac{1}{c}\) \(\frac{k}{ω}\) 

or c = \(\frac{ω}{k}\) 

\(\frac{3.6\times 10^{15}}{1.2\times 10^7}\) 

= 3 × 108 m/s



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