

InterviewSolution
Saved Bookmarks
1. |
The magnetic field perpendicular to the plane of a conducting ring of radius `r` change ate the rate `(dB)/(dt)`A. The emf induced in the ring is `pir^(2)(dB)/(dt)`B. The emf induced in the rintg is `2pir(dB)/(dt)`C. The potential difference between diametrically opposite points on the ring is half of the induced emf.D. All points on the ring are at the same potential. |
Answer» Correct Answer - A::D |
|