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The magnetic flux `phi` (in weber ) in a closed circuit of resistance 10`Omega` varies with time t (in secnod) according to equation `phi=6t^(2)-5t+1`. The magnitude of induced current at `t=0.25` s isA. `0.2A`B. 0.6AC. 1.2AD. 0.8A |
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Answer» Correct Answer - A We know that `e = - (dphi)/(dt)` ` = -(d)/(dt) (6t^(2) - 5t+1)` ` e=- 12 t + 5` ` e= - 12 xx 0.25 + 5 = 2V` `therefore " " I =(e )/(R) = (2)/(10) = 0.2A` Reading of the ammeter. |
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