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The magnetic induction at the centre of a current carrying circular coil of radius `10cm` is `5sqrt(5)` times the magnetic induction at a point on its axis. The distance of the point from the centre of the coild in `cm` isA. 5B. 10C. 20D. 25 |
Answer» Correct Answer - 3 `B=(mu_(0)nir^(2))/(2(r^(2)+x^(2))^(3//2))` |
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