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The magnetic moment of `._25Mn` in ionic state is `sqrt(15)B.M`, then Mn is in:A. `+2` stateB. `+3` stateC. `+4` stateD. `+5` state |
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Answer» Correct Answer - C `sqrt(15)=sqrt(n(n+2)),n=3,"and three unpaired electrons are found when Mn is in" Mn^(4+) i.e,3d^(3)4s^(0)` "configuration as its metal electrons configuration is "[Ar]^(18)3d^(5)4s^(2)` |
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