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The magnetic moment of a bar magnet of geometric length 20 cm is `3.6xx10^(-6) Am^(2)` The magnetic length is 90% of its geometric length the pole strength isA. `2xx10^(-5)Am`B. `1.8 xx10^(-4) Am`C. `7.2 xx10^(-8) Am`D. `0.55 xx 10^(-4) Am` |
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Answer» Correct Answer - A `2l=(5)/(6)xx"geo.length"` `(5)/(6)xx20=(100)/(6)cm` Now" "m`=(M)/(2l)=(3.6xx10^(-6)xx6)/(100xx10^(-2))` `19.6xx10^(-6)` `2xx10^(-5)Am` |
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