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The magnetic moment of a current (i) carrying circular coil of radius (r) and number of turns (n) varies asA. `1//r^2`B. `1//r `C. `r `D. `r^(2) ` |
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Answer» Correct Answer - D From the formula , the magnetic moment of a current carrying circular coil is given by `M=niA-nipir^2` where , r is the radius of circular coil. Therefore , magnetic moment is proportional to ` r^(2)`. |
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