1.

The magnetic moment of a transition metal ion is sqrt(15) B.M. Therefore the number of unpaired electrons present in it is

Answer»

4
1
2
3

Solution :Magnetic MOMENT `=sqrt(N(n+2))`
where n=no. of unpaired electrons
GIVEN `mu=sqrt(15)`
`:.sqrt(15)=sqrt(n(n+2))implies15=(n+2)`
This is POSSIBLE only when n=3.


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