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The magnetic moment produced in a substance of `1 gm is 6xx10^(-7) "ampere","metre"^(2)`. If its density is `5 gm//cm^(3)`, then the intensity of magnetisation in `A//m` will beA. `8.3xx10^(6)`B. `3.0`C. `1.2xx10^(-7)`D. `3 xx 10^(-6)` |
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Answer» Correct Answer - B Intensity of magnetisation , `l=(M)/V=-(M)/("mass/density")` Given , mass =1 g =`10^(-3)kg ` and density ` =5g//cm^(3)=(5 xx 10^(-3)kg)/((10^(-2))^(3))=5 xx 10^(3) kg m^(-3)` Hence , `l=( 6xx 10^(-7) xx 5 xx 10^(3))/( 10^(-3))=3Am^(-1)` |
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