1.

The magnetic moment (spin only) of [NiCl_(4)]^(2-) is :

Answer»

2.82 BM
1.41 BM
1.82 BM
5.46 BM

SOLUTION :In `[NiCl_(4)]^(2-), Ni^(2+): 3D^(8)4S^(@)`

No. of unpaired electrons = 2
Magnetic moment, `u=SQRT(n(n+2))`
`=sqrt(2(2+2))=2sqrt(2)=2xx1.414=2.828BM`


Discussion

No Comment Found

Related InterviewSolutions