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The magnifying power of a microscope with an objective of `5 mm` focal length is 400. The length of its tube is `20cm.` Then the focal length of the eye`-` piece isA. 200 cmB. 160 cmC. 2.5 cmD. 0.1 cm |
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Answer» Correct Answer - C (c) We assume that final image is formed at infinity, and `M_(prop)=((L_(oo)-f_(o)-f_(e))cdotD)/(f_(o)f_(e))=(LD)/(f_(o)f_(e))` or `400=(20xx25)/(0.5xxf_(e))` `f_(e)=2.5cm` |
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