The magnitude of acceleration of a point on the wheel's rim at t = 1 s, whose radius is 2 m and is spinning with angular velocity ω that varies with time as 10t^2 rad/s, is (1) 40\sqrt{26} m/s^2 (2) 40 m/s^{2 }(3) Zero (4) 20 m/s^{

The magnitude of acceleration of a point on the wheel's rim at t = 1 s

1.	The magnitude of acceleration of a point on the wheel's rim at t = 1 s, whose radius is 2 m and is spinning with angular velocity ω that varies with time as 10t^2 rad/s, is (1) 40\sqrt{26} m/s^2 (2) 40 m/s^{2 }(3) Zero (4) 20 m/s^{
Answer» The magnitude of acceleration of a point on the wheel's rim at t = 1 s, whose radius is 2 m and is spinning with angular velocity ω that varies with time as 10t^2 rad/s, is (1) 40\sqrt{26} m/s^2 (2) 40 m/s^{2 }(3) Zero (4) 20 m/s^{

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The magnitude of acceleration of a point on the wheel's rim at t = 1 s, whose radius is 2 m and is spinning with angular velocity ω that varies with time as 10t^2 rad/s, is (1) 40\sqrt{26} m/s^2 (2) 40 m/s^{2 }(3) Zero (4) 20 m/s^{

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