"The magnitude of average velocity is equal to average speed". This statement is not always correct and not always incorrect. Explain with example,

"The magnitude of average velocity is equal to average speed". This st

1.	"The magnitude of average velocity is equal to average speed". This statement is not always correct and not always incorrect. Explain with example,
Answer» Solution : Supose, a car taken 18 s to move from O (0) to P (360. Noe in next 6s, it returns from P to Q (240) then by calculating average velocity and average speed the answer of this QUESTION can be explained. For motion for O to P, Average speed `= (OP)/(t _(1)) = (+ 360)/(18) = 20 ms ^(-1)` Aberage velocity `= ("Position of P-Position of Q")/(t _(1))` `= (360-0)/(18)= (360)/(18)=20 ms ^(-1)` Here, both are equal, For motion from P to Q, Avewrage speed `= (OP +PQ)(t _(2)) -= (360)/(t_(1) + 6)` `[ because PQ =360 - 240 = 120]` ` = (480 )/(18 + 6) = (480)/(24) = 20 ms ^(-1)` Average velocity `= (Position Q-Position Of O")/(t _(2))` `= (240)/(24)= 10 ms ^(-1)` Here, both are not equal .