The magnitude of Orbital angular momentum of an electron is given by=�

1.	The magnitude of Orbital angular momentum of an electron is given by=√5h/π. How many orbitals of this type are possible belonging to an Orbit?
Answer» Answer: See below. Explanation: We are given the orbital angular MOMENTUM as, $L=\dfrac {\sqrt {5}H}{\pi }$ According to the Bohr's model, $L=<klux>N</klux>\dfrac {H}{2\pi }$ Where n = 1, 2, 3 or any POSITIVE integer values. Hence, the angular momentum is an integral multiple of H/2 pi. Square Root of 5 is not an integer. Hence, no orbitals will possess an angular momentum as given.

The magnitude of Orbital angular momentum of an electron is given by=√5h/π. How many orbitals of this type are possible belonging to an Orbit?

Answer»

Answer:

See below.

Explanation:

We are given the orbital angular MOMENTUM as,

$L=\dfrac {\sqrt {5}H}{\pi }$

According to the Bohr's model,

$L=<klux>N</klux>\dfrac {H}{2\pi }$

Where n = 1, 2, 3 or any POSITIVE integer values. Hence, the angular momentum is an integral multiple of H/2 pi.

Square Root of 5 is not an integer. Hence, no orbitals will possess an angular momentum as given.