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The magnitude of the vector `hati+xhatj+3hatk` is half of the magnitude of vector `hati+xhatj+3hatk` The values of x areA. `-2//3`B. `1//3`C. `2//3`D. `2` |
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Answer» Correct Answer - A Given, `i+xj+3k=veca" "...(1)` `and4i+(4x-2)j+2k=vecb" "...(ii)` From (ii), `|vecb|=sqrt(16+(4x-2)^(2)+4)=sqrt(16x^(2)-16x+24)` Also, `|vecb|=2|veca|` Substituting the values, we get `sqrt(16x^(2)-16x+24)=2sqrt(10+x^(2))` Solving, `(x-2)(3x+2)=0` `thereforex=2,-2//3" "]` |
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