1.

The major product in the following reaction is CH_(3)-underset(H)underset(|)overset(CH_(3))overset(|)(C)-CH_(2)Br underset(CH_(3)OH)overset(CH_(3)O^(-))to

Answer»

`CH_(3)-UNDERSET(H)underset(|)overset(CH_(3))overset(|)(C)-CH_(2)OCH_(3)`
`CH_(3)-underset(OCH_(3))underset(|)(C)H-CH_(2)CH_(3)`
`CH_(3)-overset(CH_(3))overset(|)(C)=CH_(2)`
`CH_(3)-underset(OCH_(3))underset(|)overset(CH_(3))overset(|)(C)-CH_(3)`

Solution :Since `CH_(3)O^(-)` is a strong nucleophile as well as a strong base, therefore, it can either bring about substitution or ELIMINATION. Now, the `CH_(3)` group at `BETA`-carbon causes steric hindrance to nucleophiolic substitution `(S_(N)2)`, therefore, elimination `(E_(2))` occurs preferentially to form 2-methylpropene


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