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The Marina trench is located in the Pacific Ocean, and at one place it is nearly eleven km beneath the surface of water. The water pressure at the bottom of the trench is about 1.1 xx 10 ^(8)Pa. A steel ball of initial volume 0.32 m^(3) is dropped into the ocean and falls to the bottom of the trench. What is the change in the volume of the ball when it reaches to the bottom ?

Answer» <html><body><p></p>Solution :`P =1.1 xx 10 ^(<a href="https://interviewquestions.tuteehub.com/tag/8-336412" style="font-weight:bold;" target="_blank" title="Click to know more about 8">8</a>) pa` <br m=""/> `B =1.6 xx 10 ^(<a href="https://interviewquestions.tuteehub.com/tag/11-267621" style="font-weight:bold;" target="_blank" title="Click to know more about 11">11</a>) <a href="https://interviewquestions.tuteehub.com/tag/nm-579234" style="font-weight:bold;" target="_blank" title="Click to know more about NM">NM</a> ^(-2)` <br/> <a href="https://interviewquestions.tuteehub.com/tag/bulk-403774" style="font-weight:bold;" target="_blank" title="Click to know more about BULK">BULK</a> modulus `B = (P)/((Delta V)/(V))` (<a href="https://interviewquestions.tuteehub.com/tag/magnitude-1083080" style="font-weight:bold;" target="_blank" title="Click to know more about MAGNITUDE">MAGNITUDE</a>) <br/> `B = (PV)/(Delta V) ` <br/> `therefore Delta V =(PV)/(B) = (1.1 xx 10 ^(8) xx 0.3)/(1.6 xx 10 ^(11))=22 x 10 ^(-5)` <br/> `~~ 2.2 xx 10 ^(-4) m ^(3)` <br/> Notye : Answer of Text-book is not matching, if for steel B = 140 GPa, then the answer of Text-book will be `Delta V =2.51 xx 10 ^(-4) m ^(3).`</body></html>


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