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The mass and diameter of a planet have twice the value of the corresponding parameters of earth. The acceleration on the surface of planet ......... |
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Answer» `9.8 m//sec^2` `G = (GM_e)/(R_e^2)` Acceleration of gravity on the surface of PLANET `g_p=(GM_e)/R_e^2` but `M_p = 2M_e ` here `R_p = 2R_e` `:. g_p =(G(2M_e))/((2R_e^2))=(2GM_e)/(4R_1^2)=1/2(GM_e)/(R_e^2)` `:. g_p =g/2 =(9.8)/2 m//s^2` |
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