The mass and the radius of a planet are twice that of earth. Then period of oscillation of a second pendulum on that planet will be :

The mass and the radius of a planet are twice that of earth. Then peri

1.	The mass and the radius of a planet are twice that of earth. Then period of oscillation of a second pendulum on that planet will be :
Answer» `2 sqrt(2)s` `(1)/(2)s` `(1)/(sqrt(2))s` 2 s Solution :On earth `G=(GM)/(R^(2))` On PLANET, `g'=(Gxx2M)/((2R)^(2))=(g)/(2)` `(T)/(T)= sqrt((g)/(g'))= sqrt((g)/(g//2))= sqrt(2)` `T'= sqrt(2)xxT= sqrt(2)XX 2=2 sqrt(2)`