The mass and volume of a body and found to be 4 pm 0.03 kg and 5 pm 0.01 m^(3) respectively. Then find the maximum possible percentage error in density.

The mass and volume of a body and found to be 4 pm 0.03 kg and 5 pm 0.

1.	The mass and volume of a body and found to be 4 pm 0.03 kg and 5 pm 0.01 m^(3) respectively. Then find the maximum possible percentage error in density.
Answer» SOLUTION :Mass m = `4 pm 0.03` kg `(m + DELTAM)` Volume V = `5 pm 0.01 m^(3) (V + DeltaV)` Density = ? Error in mass = `(Deltam)/(m) = (0.03)/(4) xx 100 = 0.75%` Error in volume `= (DeltaV)/(V) = (0.01)/(5) xx 100 = 0.2%` Density = `("mass")/("volume")` Error in density = error in mass + error in volume = 0.75% + 0.2% = 0.95%