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The mass in grams of 0.45 mole of Ca^(2+) ions |
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Answer» ` Ca to Ca^(2+) + 2e^(-)` 41 g of Ca = 1 mole (for `Ca^(2+)` = Atomic mass remains same) 1 mole of `Ca^(2+)` = 40 g `:.` 0.45 mole of `Ca^(2+)=40/1xx0.45=18g` |
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