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| 1. |
The mass number and the atomic number of uranium are 238 and 92 respectively. If on nuclear disintegration 6 alpha- and 4 beta-particles are emitted, find the mass number and atomic number of the atom formed. |
| Answer» Solution :APPLYING group DISPLACEMENT law, EMISSION of `6 alpha`-PARTICLES will cause a decrease in mass number 24 `(6 xx4)` units and in atomic number by `12(6 xx 2)` units. Now with the emission of `4 beta`-particles, mass number will not change but atomic number will increase by 4 units. Thus the mass number and the atomic number of the atom formed will be 214 (i.e. 238-24) and 84 (i.e., `92-12+4`) respectively. | |