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The mass of 1.2 cm^3 of a certain substance is 5.74g. Calculate its density with due regard to significant figures. |
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Answer» SOLUTION :Mass, m= 5.74g, volume, V= `1.2 CM^(3)` density, `d= (m)/(v) = (5.74g)/(1.2 cm^(3))` 5.74 has significant digits and 1.2 has two significant digits. no need for rounding off, `therefore d = (5.74)/(1.2)= 4.783333`. This is to be rounded off to two significant digits. The density of the given SUBSTANCE is `4.783 = 4.8 g cm^(-3)` |
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