1.

The mass of 1 litre of helium under a pressure of 2 atm and at a temperature of 27^(@)C is

Answer»

0.16 g
0.32 g
0.48 g
0.64 g

Solution :`"No. of moles (n)"=(PV)/(RT)=(2xx10^(5)xx10^(-3))/(8.3xx300)=0.08`
`"MASS of one ofHe"=4G`
`"Mass of n moles "=(nxx4)=(0.08xx4)=0.32g`


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