1.

The mass of 2.24 xx 10^(-3) m^(3) of a gas is 4.4 g at 273.15K and 101.325 kPa pressure. The gas may be

Answer»

NO
`NO_(2)`
`C_(3) H_(8)`
`NH_(3)`

Solution :m = 4.4 g , V = `2.24 xx 10^(-3) = 2.24 L`
T = 273.15 K
p= 101. 325kPa
= 101325Pa = 1 atm
pV = NRT or pV `= ( m )/( M ) RT `
or `M = ( m RT )/( pV )`
` = ( 4.4 xx 0.0821 xx 273.15)/( 1 xx 2.24 ) = 44.05 `
`:.` The gas is `C_(3) H_(8)`


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