1.

The mass of 2.24xx10^(-3)m^(3) of a gas is 4.4 g at 273.15 K and 101.325 kPa pressure. The gas may be

Answer»

NO
`NO_(2)`
`C_(3)H_(8)`
`NH_(3)`

SOLUTION :`2.24xx10^(-3)m^(3)` of a gas = 2.24 L at STP
Thus, 2.24 L of the gas at STP WEIGHT = 4.4 g
`therefore 22.4` L of the gas at STP will weigh = 44 g
But 22.4 L of a gas at sTP = Molar mass of the gas
`therefore " Molar mass of the gas = 44 g"`


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