1.

The mass of a body is `5xx10^(-6)kg.` What is this mass in `(alpha)` gram (b) milligram (c ) microgram?

Answer» Here, `n_1 = 5xx10^(-6), u_1 = 1kg`
`n_2 = ? U_2 =1 gram`
From `n_2 u_2 =n_1u_1 =n_2 = (n_1u_1)/(u_2) =(5xx10^(-6)xx1kg)/(1 gram) = (5xx10^(-6)kg)/(10^(-3)kg) = 5xx10^(-3)g`
(b) `n_2 =? U_2 =1 milligram`
`n_2 = (n_1u_1)/(u_2) =(5xx10^(-6)xx1kg)/(1 milligram) =(5xx10^(-6)kg)/(10^(-6)kg) = 5mg`
(c ) `n_2 =? u_2 = 1 microgram`
`n_2 = (n_1u_1)/(u_2) = (5xx10^(-6)xx1kg)/(1 microgram) = (5xx10^(-6)kg)/(10^(-9)kg) = 10^3 microgram`


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