1.

The mass of a gas that occupies a volume of 612.5 ml at room temperature and pressure (25^(@)C and 1 atm pressure) is 1.1 g. The molar mass of the gas is

Answer»

66.25 G `mol^(-1)`
44 g `mol^(-1)`
24.5 g `mol^(-1)`
662.5 g `mol^(-1)`

Solution :No. of moles of a gas that occupies a volume of 612.5 ml at room temperature and PRESSURE (`25^(@)`C and 1 atm pressure)
`612xx10^(-3)L//24.5molL^(-1)`
0.025moles
We know that,
Molar mass=Mass no. /no. of moles
1.1g/0.025 mol=44g `mol^(-1)`


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