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The mass of a gas that occupies a volume of 612.5 ml at room temperature and pressure (25^(@)C and 1 atm pressure) is 1.1 g. The molar mass of the gas is |
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Answer» 66.25 G `mol^(-1)` `612xx10^(-3)L//24.5molL^(-1)` 0.025moles We know that, Molar mass=Mass no. /no. of moles 1.1g/0.025 mol=44g `mol^(-1)` |
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